4x^2+60x+176=0

Solution for 4x^2+60x+176=0 equation:

4x^2+60x+176=0

a = 4; b = 60; c = +176;
Δ = b2-4ac
Δ = 602-4·4·176
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-28}{2*4}=\frac{-88}{8}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+28}{2*4}=\frac{-32}{8}
=-4
$